What is the number of diagonals in polygon with N sides?

The number of diagonals in a polygon is given by n(n-3)/2.

How do you find the sides of a polygon given the diagonals?

By using the formula for the number of diagonals of a polygon with n sides, you can determine how many sides a polygon has if you know the number of diagonals it has. For example, if a polygon has 54 diagonals, find how many sides it has. Then, solve for n using algebra. First multiply both sides by 2.

How many sides does a polygon have if the maximum number of diagonals that you can draw inside it is 54?

12
So, the number of sides of a polygon which have 54 diagonals is 12.

How do you find the angle of an N-sided polygon?

The sum of the interior angles, in degrees, of a regular polygon is given by the formula 180(n – 2), where n is the number of sides.

How many diagonals does a regular n gon have?

9 diagonals
Therefore, the number of diagonals in a polygon pentagon is 5. For n = 6, n-polygon is called hexagon and it has 9 diagonals.

What is the formula to find the sides of a polygon?

Answer: To find the number of sides of a polygon when given the sum of interior angles, we use the formula: Sum of interior angles = (n – 2) × 180, where n is the number of sides.

How many sides has a regular polygon with 35 diagonals?

10
So, the number of sides of a polygon having 35 diagonals is 10.

How many sides does a regular polygon have that has 44 diagonals?

11
Hence, the number of sides in a polygon which has 44 diagonals is 11.

How many diagonals are in a polygon with n sides?

How many diagonals are there in a polygon with n sides? A polygon of n sides has n vertices. By joining any two vertices of a polygon, we obtain either a side or a diagonal of the polygon. Number of line segments obtained by joining the vertices of an n sided polygon taken two at a time

How do you find the number of diagonals in a decagon?

However, that counts each diagonal exactly twice (once from each side), so the actual number of diagonals is half that: d= (n) (n-3)/2. Now we can look at the polygon above, and use it to check this formula, by “remembering” that it is a decagon. With n = 10, d = ( n ) ( n -3)/2 = (10) (7)/2 = 35. Are there really 35 diagonals in the decagon above?

How do you calculate the number of diagonal lines in a graph?

But it’s simple: For each vertex (n), there is one diagonal linking for all vertex, except the same vertex and the two neighbours (n-3). Thus you have n (n-3), that you got to divide by two or else each diagonal will be counted going and coming back.