Which is the smallest number that leaves a remainder of 4 each when divided by 9 15 and 18?
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Which is the smallest number that leaves a remainder of 4 each when divided by 9 15 and 18?
The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: [A]. Explanation: L.C.M. of 6, 9, 15 and 18 is 90.
What is the lowest number which leaves 4 as remainder when divided by 9 and 12?
the lowest number divisible 9 and 12 is 36. ∴ Adding 4 to 36 we get 40. Hence the required number is 40, which gives remainder 4 when divided by 9 and 12. So, the lowest number is 40.
What is the smallest number which leaves remainder 3 when?
the answer to this question is 843.
What is the smallest number which has remainder 3 when divided by 5 7 and 8?
Hence 1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.
Which is the smallest multiple of 7?
Every number is the smallest multiple of itself. Number 7 has infinite multiples as it can be multiplied with any whole number and we have infinite whole numbers. A multiple can be the common multiple of two or more numbers….First 20 Multiples of 7.
| Multiplication | Multiples of 7 |
|---|---|
| 7 × 1 | 7 |
| 7 × 2 | 14 |
| 7 × 3 | 21 |
| 7 × 4 | 28 |
Which is the smallest number when divided by 18 and 12 leaves remainder 3?
So, The Smallest number is 36 + 3 = 39 which leaves a remainder 3 when divided by 12 and 18.
What is the smallest number that leaves remainder of 4?
So 4 is the smallest such number. To find other numbers that leave remainder of 4, you have to add multiples of the least common multiple (LCM) of 8, 12 and 14 to the smallest number. You can calculate the LCM by inspection of prime factors: 8=2^3, 12=3*2^2, 14=7*2.
What is the smallest number when divided by 28 and 32?
The smallest number when divided by 28 and 32 leaves remainder 8 and 12 respectively:- 28 – 8 = 20 and 32 – 12 = 20 are divisible by the required numbers. Therefore, the required number will be 20 less than the LCM of 28 and 32. Prime factorization of 28 = 2 x 2 x 7 Prime factorization of 32 = 2 x 2 x 2 x 2 x 2
Which number when divided by 7 8 and 9 leaves remainder?
The smallest possible value of c = 0. Originally Answered: What is the smallest no. which when divided by 7, 8 and 9 leaves remainder 2, 4 and 6 respectively? Explanation please. If a number when divided by 8 gives remainder 4, then it is divisible by 4. If a number when divided by 9 gives remainder 6, then it is divisible by 3.
What is the smallest 4 digit number that is divisible by 6?
The smallest 4 digit number which is divisible by 6 is 1002. Adding 5 to it gives 1007. Hence the series should be 1007,1013,1019 etc. Hence the smallest four digit number which when divided by 6 leaves reminder 5 and when divided by 5 leaves reminder 3 is 1013.