What is the vertical component of a force of 10N acting at 30 degree to the horizontal?

The vertical component of that force is zero, because here angel between the force and vertical component is 90.

What is the component of force of 10N in a direction perpendicular to it?

Answer: If a 10N force is directed down towards the ground (-y direction) then the x component (perpendicular to y by definition of Cartesian coordinates) will be 0.

How is a moment defined in physics?

A moment is the turning effect of a force. Moments act about a point in a clockwise or anticlockwise direction. The point chosen could be any point on the object, but the pivot – also known as the fulcrum – is usually chosen. moment (M) is measured in newton-metres (Nm) force (F) is measured in newtons (N)

How do you find the X component?

Well the scalar product of two vectors A and B is |A|*|B| cos theta where the “|” denote the scalar magnitude. So to find the x-component, form the vector c = (1,0) and form the product as above (with your input vector), then divide by the length (magnitude!) and take the arc-cosine of the result.

What is the x component of the net force?

These parts of the force are called the components of the force. The component that pushes right or left is called the x-component, and the part that pushes up or down is called the y-component. Mathematically, the components act like shadows of the force vector on the coordinate axes.

What is the magnitude of the force on the x-axis?

The magnitude, but not direction, would be the same if the force is measured clockwise or counterclockwise from the y-axis. 30deg clockwise from the y-axis is a 90–30=60deg angle. The x-component will be Fx=10cos60=10 (1/2)=5 N. The force F of 10N makes an angle of 60° with x-axis. Draw a line making a an angle of 60° with x-axis.

What is the X magnitude of 30 – 60 – 9 0?

Since this force does make an angle of 30 ∘ with the y-axis we now have a 30 ∘ – 60 ∘ − 9 0 ∘ right triangle. To find the x magnitude we take the sin of 30 ∘ × the force of 10N (hyp.) or sin 30 ∘ = x/10N ===> x = 10N ⋅ sin30 ∘ ===> x = 5 N

How do you find the sin of a force of 10n?

One easy tip- The side with the angle is always Cos and the side away from angle is Sin. A force of 10N makes an angle of 30° with y-axis. Find the magnitude of x-component?

What is the Y component of a force vector?

In the given question force of 100 N makes an angle of 60 degree with the Y-axis and hence it makes an angle of 30 degree with the X-axis and hence the Y component of the force vector will be Fsin30 i.e. 100*sin (30) Y component of force 100*sin (30) =50N. How do I render a vector graphic using C#?