What are the conditions for maximum range?

The range is maximum when sin2θ is maximum. So, for two angles, θ and 90 – θ the range of the projectile will be same.

When the range of projectile is maximum when it is zero?

The maximum height of the projectile is when the projectile reaches zero vertical velocity. From this point the vertical component of the velocity vector will point downwards. The horizontal displacement of the projectile is called the range of the projectile and depends on the initial velocity of the object.

When the range of projectile is minimum?

When θ = 90°, sin 2θ = sin 180° = 0. Hence, the range covered becomes 0. Since range cannot be negative, 0 is the minimum value it can attain.

What is mean by maximum horizontal range for a projectile What are the factors that depend on it?

The horizontal distance depends on two factors: the horizontal speed (vox) and the time the projectile has been in the air. The horizontal distance is the product of these two quantities. The height of the projectile depends on the original vertical speed (voy) and the time that the projectile has been in the air.

When the projectile is at the highest point of its trajectory the direction of its velocity and acceleration are?

Direction of velocity is always tangent to the path so at the top of trajectory, it is in horizontal direction and acceleration due to gravity is always in vertically downward direction. It means angle between →v and →g are perpendicular to each other.

What is the maximum effective range of a 9mm pistol?

If you define effective range as distance that a shooter can deliver a hit to a man sized target, then the maximum effective range for a 9mm round fired from a handgun is about 1800 meters. If that sounds like a ridiculously long distance, that’s because it is.

What is the horizontal range of a projectile?

The horizontal range of a projectile is the distance along the horizontal plane it would travel, before reaching the same vertical position as it started from. The horizontal range depends on the initial velocity v0, the launch angle θ, and the acceleration due to gravity. The unit of horizontal range is meters (m).

What is the equation for projectile motion?

Let’s sum that up to form the most important projectile motion equations: Horizontal velocity component: vx = v * cos(θ) Vertical velocity component: vy = v * sin(θ) Time of flight: t = 2 * vy / g Range of the projectile: R = 2* vx * vy / g Maximum height: ymax = vy^2 / (2 * g)