How do you find the zeros at the end of a factorial?

If you want to figure out the exact number of zeroes, you would have to check how many times the number N is divisible by 10. When I am dividing N by 10, it will be limited by the powers of 2 or 5, whichever is lesser. Number of trailing zeroes is going to be the power of 2 or 5, whichever is lesser.

What is the last nonzero digit in factorial of 96?

How to find the last non zero digit in 96 factorial. 96 = 5*19+1.

How many zeros are there at the end of 1000 factorial?

Hence there are 249 zeros at the end of 1000!.

What is the last nonzero digit in 20?

So the last non-zero digit is 4. There are two methods you may use to find the last non-zero digit in 20! The last non-zero digit in N! is same as the last non-zero digit in (N/5)! ×(2^(N/5))×(N/5rem)!

What is the last nonzero digit of 50?

So 50! has 12 zeros which means that the last digit of 50! 1012 is the number that i´m looking for.

How do you find the last digit of a factorial?

Given a number n, we need to find the last digit in factorial n. 4! = 4 * 3 * 2 * 1. = 24. Last digit of 24 is 4. 5! = 5*4 * 3 * 2 * 1. = 120. Last digit of 120 is 0. A Naive Solution is to first compute fact = n!, then return the last digit of the result by doing fact \% 10.

How do you find the last non-zero digit of a given number?

A Simple Solution is to first find n!, then find last non-zero digit of n. This solution doesn’t work for even slightly large numbers due to arithmetic overflow. Let D (n) be the last non-zero digit in n!

How to solve factorials with naive and efficient solutions?

A Naive Solution is to first compute fact = n!, then return the last digit of the result by doing fact \% 10. This solution is inefficient and causes integer overflow for even slightly large value of n. An Efficient Solution is based on the observation that all factorials after 5 have 0 as last digit. ………….. // digit in factorial n. # factorial n.

How many zeroes does 1750 a 2 +250A + 12 have?

So last two digits of this expression depends on 1750 a 2 +250a + 12 We try to find the last two digits of 1750 a 2 +250a. Taking 250 common Now If a is odd, 7 a 2 + a is even so which contributes another 2. So 1750 a 2 +250a has two zeroes. If a is even, 1750 a 2 +250a clearly gives two zeroes.