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How do you calculate the amount of heat required to convert ice to steam?

How do you calculate the amount of heat required to convert ice to steam?

The heat required to convert 25 grams of -10 °C ice into 150 °C steam is 78360 J or 78.36 kJ….In this problem:

  1. q =?
  2. m = 25 g.
  3. c = (2.09 J/g·°C.
  4. ΔT = 0 °C – -10 °C (Remember, when you subtract a negative number, it is the same as adding a positive number.)

How much heat is required to change 1g of ice at exactly 0 C to steam at 100 C?

Total heat required to convert 1 g of ice at 0°C into steam at 100°C is 716 cal.

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How much energy is required to change a 40.0 g ice cube from ice to C at 110 C?

How much thermal energy is required to change a 40 g ice cube from a solid at -10 oC to steam at 110 oC? ΔQ = 0.04 kg*(0.49 kcal/(kgoC))*10 oC = 0.196 kcal. ΔQ = 0.04 kg*80 kcal/kg = 3.2 kcal.

How much heat must be added to 100 g of ice at 0 C to melt the ice completely?

Converting 100. g of ice at 0.00 °C to water vapour at 100.00 °C requires 301 kJ of energy.

What is the specific heat of ice in joules?

2093
Specific Heats of Various Substances

Substance Specific Heat (cal/gram C) Specific Heat (J/kg C)
Ice (0 C) 0.50 2093
sandy clay 0.33 1381
dry air (sea level) 0.24 1005
quartz sand 0.19 795

How much heat must be added to a 1g of ice at 0 C to change it all to 0 C water?

This means that to convert 1 g of ice at 0 ºC to 1 g of water at 0 ºC, 334 J of heat must be absorbed by the water.

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How much energy is required to change a 40.0 g?

1.22×105J.

How much heat does it take to convert 50g of ice at 0 C to liquid water at 95 C?

Ernest Z. The amount of heat required is 36 kcal.

What is the amount of heat required to convert ice to steam?

The amount of heat required to convert 1 g of ice (specific 0.5 cal at g^-1o C^-1 ) at – 10^0 C to steam at 100 ^∘ C is .[ Given: Latent heat of ice is 80 Cal/ gm, Latent heat of steam is 540 Cal/gm , Specific heat of water is 1 Cal/gm/C ]

How much energy does it take to convert 100g ice to water?

Converting 100. g of ice at 0.00 °C to water vapour at 100.00 °C requires 301 kJ of energy. q1 = heat required to melt the ice to water at 0.00 °C. q2 = heat required to warm the water from 0.00 °C to 100.00 °C. q3 = heat required to vapourize the water to vapour at 100 °C.

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What is the amount of heat required to melt ice?

725 cal Amount of heat required = Change the temp Of Ice from -10 C to 0 C + Heat required to melt the Ice + Heat required to increase the temperature of water from 0 to 100 C + Heat required to convert water  at 100 C to vapor at 100 C =1×0.5[0−(−10)]+1×80+1×1×100+1×540=5+80+100+540=725cal

What is the specific heat of steam and water?

specific heat of water = 4.18 J/g·°C. specific heat of steam = 2.09 J/g·°C. Solution: The total energy required is the sum of the energy to heat the -10 °C ice to 0 °C ice, melting the 0 °C ice into 0 °C water, heating the water to 100 °C, converting 100 °C water to 100 °C steam and heating the steam to 150 °C.