Q&A

Does the series ∑ n 1 ∞ an converge or diverge?

Does the series ∑ n 1 ∞ an converge or diverge?

3. Answer: Since ln n ≤ n for n ≥ 2, we have 1/ ln n ≥ 1/n, so the series diverges by comparison with the harmonic series, ∑ 1/n. ∞ n=1 1 (2n)!

Does n 1 n n converge?

n=1 an, is called a series. n=1 an diverges. n=1 an converges then an → 0. n=1 an diverges.

Does the series 1 n n converge?

1 n diverges and the alternating harmonic series converges.

Does the series N diverge?

If the limit of |a[n+1]/a[n]| is less than 1, then the series (absolutely) converges. If the limit is larger than one, or infinite, then the series diverges.

Does the series converge or diverge?

If you’ve got a series that’s smaller than a convergent benchmark series, then your series must also converge. If the benchmark converges, your series converges; and if the benchmark diverges, your series diverges. And if your series is larger than a divergent benchmark series, then your series must also diverge.

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Does σ1/n converge or diverge?

I haven’t taken calculus in a while, but if I remember correctly, Σ1/n is a special type of P-Series called a Harmonic Series, and those series diverge. Remember, converges. Now, surprisingly, diverges. There are many ways to test the convergence of this series, but the best is Adnan’s answer.

How does the series n/(n+1) converge to 1?

Answer: The series n/ (n+1) will converge to 1 as n → ∞ . For problems of this kind, the answer is obtained just by looking at the problem then and there; but writing the steps takes quite a bit of time and one may not be inclined to do that at all times.

Why does $sum_n(n+1)^{-1} diverge?

That is kind of important! As a sequence it converges to $1$, as a series, $\\sum_n (n+1)^{-1}$ diverges since the sequence is not a null-sequence.$\\endgroup$ – Jakob Elias May 17 ’17 at 14:53

Why does the series diverge when p = 1?

Whenever p ≤ 1, the series diverges because, to put it in layman’s terms, “each added value to the sum doesn’t get small enough such that the entire series converges on a value.” I haven’t taken calculus in a while, but if I remember correctly, Σ1/n is a special type of P-Series called a Harmonic Series, and those series diverge.