Which has largest size O or O2?

O2− is larger than O because the increase in electron repulsions that accompany addition of an electron causes the electron cloud to expand. O2− is larger than O because O is neutral but O2− has a charge 2−.

Which is correct order of size of O O2 F F?

O2−>O−>F−>F.

Does O2 or O have a larger atomic radius?

O and O2− have an equal atomic number which is 8. However, the two species have different numbers of electrons, O has 8 while O2− has 10. This means that the latter has larger orbitals and less tightly held outer electrons. Therefore, O2− has a larger atomic radius.

Which of the following f/o O2 F is largest in size?

However, now left to right the radius is more of a function of the number of electrons. Mg2+ is smaller than Na+. Similarly, O2- will be larger than F- as both have 10 electrons but Z=8 for oxygen and Z=9 for fluorine.

Which has smaller size O and O2?

O- has smaller size as it has only 9 e. Whereas O2- is larger because it has 10 e.

Why is O smaller than O2?

O2− is larger than O because O is neutral but O2− has a charge 2−. O2− is larger than O because the decrease in electron repulsions that accompany addition of an electron causes the electron cloud to expand.

Which is smaller O or O2?

What is the radius of O?

152 pm
Oxygen/Van der Waals radius

Is O bigger than N?

The atomic radii of nitrogen is larger than oxygen.

Which is larger S2 or O2?

As we know that the number of shells are increased while moving down the group in the periodic table, so, we conclude that the atomic size of the elements increases from top to bottom. Hence, O2− has smaller atomic radius that S2− .

Which one is larger O2 or F?

Since the nuclear charge of O2-ion is small, its size is, therefore, more than that of F-ion.

Which is bigger C or O?

Since C comes before O in the second period, O will have a smaller atomic radius than C .

Why is S2+ larger than O2+?

S2− is larger than O2− because for particles with like charges, size increases going down a family. S2− is larger than O2− because the increase in electron repulsions that accompany addition of an electron causes the electron cloud to expand. S2− is larger than O2− because S2− has more electrons than O2−.

Which is the correct order of the electron configuration for O2+?

As a particular atom gains an electron, size increases due to inter-electronic repulsions. So, order is O− >F −. Thus, O2− > O− >F − >F. Hence, option A is correct.

Why is |RMK+ larger than Ca2+?

|rmK+ is larger than Ca2+ because the increase in electron repulsions that accompany addition of an electron causes the electron cloud to expand. |rmK+ is larger than Ca2+ because K+ has the larger Z and Zeff.