What will happen to the time period of a simple pendulum if it is taken to moon length remaining unchanged?
Table of Contents
- 1 What will happen to the time period of a simple pendulum if it is taken to moon length remaining unchanged?
- 2 What effect occurs on the time period of a pendulum if it is taken from the equator to pole?
- 3 What are the factors affecting the time period of a simple pendulum?
- 4 In which condition the motion of a simple pendulum is simple harmonic?
- 5 Why does a simple pendulum oscillate slowly on the Moon?
- 6 What is the equation of time period of simple pendulum?
What will happen to the time period of a simple pendulum if it is taken to moon length remaining unchanged?
So, if g decreases it means that T(time period) will increases and the pendulum will start moving slowly when is taken to moon.
What effect occurs on the time period of a pendulum if it is taken from the equator to pole?
Since the time period has reduced, the pendulum will undergo more number of oscillations than that of at the equator. As a result, the clock at the pole will show more time than the correct time at the equator. Therefore, we can say that when the pendulum is taken to a pole, it will gain time.
What will be the impact on the duration of swinging of a pendulum if it is carried on moon?
When the simple pendulum is taken to the moon, then the value of ‘g’ (acceleration due to gravity) will decrease and hence the time period will increase. The staining effect of the pendulum on the moon will also be reduced due to the absence of air resistance and other powers which work on the Earth.
When a pendulum clock is moved from the Earth with a larger gravitational acceleration to the moon where will it go faster?
The acceleration due to gravity at the moon’s surface is only about one-sixth that at the earth’s surface. If you took a pendulum clock to the moon, would it run fast, slow, or on time? It would run slow.
What are the factors affecting the time period of a simple pendulum?
The only things that affect the period of a simple pendulum are its length and the acceleration due to gravity. The period is completely independent of other factors, such as mass.
In which condition the motion of a simple pendulum is simple harmonic?
Analyzing the forces on a simple pendulum An object is a simple harmonic oscillator when the restoring force is directly proportional to displacement. Figure 1: A simple pendulum with length l, mass m, and displacement angle θ has a net restoring force of − m g sin θ -mg\sin\theta −mgsinθminus, m, g, sine, theta.
How does length of pendulum affect period?
The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.)
What happens to the time period of a simple pendulum if it is taken from the earth to the moon where the gravity is one sixth that at the surface of the earth?
Answer: When the pendulum is taken to the moon, the value of ‘g’ will decrease and hence time period will increase.
Why does a simple pendulum oscillate slowly on the Moon?
When simple pendulum will placed on the surface of moon then its time period increases hence simple pendulum oscillates slowly. T=2π√l/g, put the value of g=1/6 because gravity on moon is one sixth as compare to the Earth.
What is the equation of time period of simple pendulum?
Mathematically, equation of time period of the simple pendulum is T=2π√l/g, put the value of g=1/6 because gravity on moon is one sixth as compare to the Earth. Then, we get the value which prove simple pendulum will works slowly.
How is mechanical energy conserved in a simple pendulum?
In a simple pendulum, the mechanical energy of the simple pendulum is conserved. If the temperature of a system changes then the time period of the simple pendulum changes due to a change in length of the pendulum.
What is the period of a pendpendulum?
pendulum’s period (for small amplitudes) isT =2πpl/g, as shownbelow, so 4π2l