What mass of o2 in grams is required for complete combustion of 25.5 g of methane?
Table of Contents
- 1 What mass of o2 in grams is required for complete combustion of 25.5 g of methane?
- 2 How many grams of oxygen react with 12g of magnesium?
- 3 How much oxygen is required for complete combustion of 560g of ethane?
- 4 How many grams of oxygen reacts with 48 grams of magnesium?
- 5 How many moles of O2 is required in the combustion reaction of methane ch4?
- 6 How many moles of oxygen are required for combustion of magnesium?
- 7 How much MgO is formed from 16G of O2 and CO2?
What mass of o2 in grams is required for complete combustion of 25.5 g of methane?
102 grams
The mass of oxygen gas needed for the complete combustion of 25.5 grams of methane is 102 grams.
How many grams of oxygen react with 12g of magnesium?
Ans: Magnesium (Mg) and Oxygen (O) combine in the ratio = 3:2 to form compound magnesium oxide (MgO). It follows Law of Constant proportions. 3g of Mg combines with = 2g of O. 12g of Mg combines with = 2 × 12/3 = 8g of O.
How much oxygen is required for complete combustion of 560g of ethane?
1.96 kg of oxygen is required.
How many moles of O2 are required for combustion of one mole of C4H10?
C4H10 + 6.5 O2 → 4 CO2 + 5 H2O. Each mole of butane needs 6.5 moles of oxygen, so 13 moles of oxygen is required for 2 moles of butane in a complete combustion.
What mass of oxygen reacts with 6g of magnesium?
Approx. a 10⋅g mass is formed.
How many grams of oxygen reacts with 48 grams of magnesium?
Two moles of magnesium reacts with one mole of oxygen gas to form two moles of magnesium oxide. Therefore 2 moles of magnesium = 48 grams. Therefore 2 moles of magnesium oxide = 80 grams. So, 48 grams of magnesium reacts with 32 grams of oxygen to form 80 grams of magnesium oxide.
How many moles of O2 is required in the combustion reaction of methane ch4?
When you burn 6.25 moles of methane, you need 12.5 moles of oxygen gas.
How many moles of oxygen are required for combustion of magnesium?
How many moles of oxygen are required for the combustion of 25.5 g of magnesium? Deliver better patient care with this online program. Learn the fundamentals of business and how to apply them in your healthcare practice. This will require 1.049 / 2 = 0.525 mol O2 for combustion.
What is the mass of 2 moles of oxygen in methane gas?
CH4 + 2O2 → CO2 + 2 H2OFor complete combustion of one mole methane 2 moles of O2 is required. Now, mass of 2 moles O2 = (2 × 32) g = 64 g.* Hope this helps. Methane burns in oxygen to give CO2 and H2O.
How much oxygen is required to produce 2 moles of Cabo dioxide?
One mole of methane completely in oxygen to give 2 mole of Cabo dioxide and 2 moles of water. 1 mole of methane reacts with 2 moles of oxygen. So the weight of oxygen required = 2 x 32 =64 gm.
How much MgO is formed from 16G of O2 and CO2?
Frm the equation 32g O2 produces 1 mole CO2. Hence 16g O2 produces 16 /32 =1/2 mole Co2. 1/2 mole CO2 contains 16 gm of oxygen. This is the answer. A 0.5 mole of magnesium burns in excess of oxygen. How much MgO is formed? 0.5 mol of MgO = 0.5 mol X 40.3 g/mol [molar mass of MgO] = 20.15 g of MgO. , A-level Chemistry.