What is the resistance across a diameter of the circle?

Howdy!! hence, the resistance across the diameter of circle is R/4.

How do you find the equivalent resistance of a circle?

The sum of the currents through each path is equal to the total current that flows from the source. You can find total resistance in a Parallel circuit with the following formula: 1/Rt = 1/R1 + 1/R2 + 1/R3 +… Rt = R (t)otal.

What is meant by equivalent resistance?

The equivalent resistance is where the total resistance connected either in parallel or in series. The equivalent resistance of a network is the single resistor which can replace the entire network in such a way that for a certain applied voltage as V we will get the same current as I.

Are distance of 10 ohm is bent in the form of a closed circle what is the effective resistance between the two points at the ends of any diameter of the circle?

Therefore, the effective resistance between the two points at the end of any diameter of the circle is $2.5ohm$. Hence, the correct option is C.

What is the equivalent resistance between the points P and Q in the network shown in the figure?

The equivalent resistance of the network shown in the figure between points P and Q is. 2. /n. Ω .

What is the resistance of a 10 ohm closed circle wire?

Once the wire is formed a closed circle, the circle makes two parallel paths (each has 5ohms ) across its diameter. And equalent resistance of two resistors of 5 ohms connected in parallel is 2.5 ohms. Originally Answered: A wire of resistance 10 ohm is bent in the form of a closed circle.

How do you calculate the equivalent resistance of a wire?

Take a diameter on circle formed by Wire and you will get two point in form of the ends of diameter , with respect to which you have to calculate the equivalent resistance. You will have a parallel combination of two equal resitance each of magnitude R/2 . Req = [R/2 * R/2] / (R/2 + R/2) = R/4 .

What is the equivalent resistance of a circular loop?

Therefore, the equivalent resistance (R) of the circular loop across its two diametrically opposite points becomes (1/4)*r of the initial resistance of the wire. Add corrections in the comment if the following answer is not exactly what you are looking for. AB is the diameter. or, two resisters in parallel.

What is the net resistance of a circle of semicircles?

When the wires are connected across the diameter, the circle can be imagined as resistors of two equal semicircles, connected in parallel. Now, a circle has resistance of 10 ohm. The semicircles will have resistance of 5 ohm each. As they are connected in parallel, net resistance is 5/2 or 2.5 ohm.