What is the probability of selecting two cards no replacement and getting two aces?

For the first ace, the probability would be 4/52, or 1/13. (without replacement) For the second ace, the probability would be 3/51 or 1/17. (with replacement) For the second ace, the probability would be 4/52 or 1/13. (without replacement) The product of these would be 1/221 or about .

How do you find the probability of drawing cards without replacement?

Explanation: The probability of two consecutive draws without replacement from a deck of cards is calculated as the number of possible successes over the number of possible outcomes, multiplied together for each case. Thus, for the first ace, there is a 4/52 probability and for the second there is a 3/51 probability.

How many cards are drawn at random from a deck?

Two cards are drawn at random (without replacement) from a regular deck of 52 cards. What is the probability that the first card is a red and the second card is heart? Let $A$ be the event that a red Stack Exchange Network

What is the probability of drawing one king from a deck?

So, probability of drawing one king from a deck of 52 cards is (4/52)=(1/13). Now,after drawing one king there are three kings left in 51 cards of the deck(as one card is drawn already). Probability of choosing another king from 51 cards is (3/51)=(1/17).

What is the probability of drawing a heart on the first draw?

Both cards are hearts: The probability of drawing a heart on the first draw is $\\Pr(H) = 13/52$. Of the $51$ cards that remain, $12$ are hearts. Hence, the probability of drawing a heart given that a heart was drawn on the first draw is $\\Pr(H \\mid H) = 12/51$.

How many cards can be drawn from a pack of 52 cards?

2 cards can be drawn from a pack of cards in 52C2 ways. And since there are 4 Kings, 2 cards can be drawn from these 4 cards in 4C2 ways. Hence, the required probability is 4C2 / 52C2. Two cards are drawn at a time from the deck of 52 cards.