What is the probability of getting a sum of 9 when a die is rolled twice?

→ Required Probability = (total Possible outcomes of sum is 9 or 11) / (total Possible outcomes) = (4/36) = (1/9) (Ans.) what is the mean deviation of the data:8,9,12,15,16,20,24,30,32,34? brainly.in/question/26616981?

Which is the probability of getting the number 9 in a die?

since there is no number 9 in a die . the propability of getting 9 is 0.

What is the probability that a number 9 Turns up in a single throw of die?

There are 36 possible outcomes. Of those, the ones that total 9 are 3-6, 6-3, 4-5, or 5-4. That makes 4 out of 36. So the probability of getting a total of 9 by throwing 2 dice is 4/36 or 1/9.

What is the probability that the sum of two rolled dice is 9 given that at least one of the dice rolled is a 4?

So, there are only 2 combos that sum to 9 and have at least 1 of the die be a 4. So the probability is: (number of combos we want)/(total number of combos) = 2/36. Reduced, this is 1/18.

What is the probability that a prime number selected at random from numbers 1 2 3 35?

Hence, the required probability of getting a prime number , P(E1) = 11/35 .

How many outcomes are there when a die is thrown twice?

When a die is thrown twice, there are 36 possible outcomes. Therefore, there are 6 outcomes that produce a sum of 4 or 10. When a die is thrown twice, there are 36 possible outcomes.

What is the probability of getting 7 on a 10-sided die?

There is a simple relationship – p = 1/s, so the probability of getting 7 on a 10 sided die is twice that of on a 20 sided die. The probability of rolling the same value on each die – while the chance of getting a particular value on a single die is p, we only need to multiply this probability by itself as many times as the number of dice.

How do you find the probability of rolling a single die?

The probability of rolling the same value on each die – while the chance of getting a particular value on a single die is p, we only need to multiply this probability by itself as many times as the number of dice. In other words, the probability P equals p to the power n, or P = pⁿ = (1/s)ⁿ.

What is the probability of rolling a 15 on a dice?

If we consider three 20 sided dice, the chance of rolling 15 on each of them is: P = (1/20)³ = 0.000125 (or P = 1.25·10⁻⁴ in scientific notation). And if you are intereseted in rolling the set of any identical values, simply multiply the result by the total die faces: P = 0.000125 * 20 = 0.0025.