What is the length of the rectangle if its area is 24 cm2?
Table of Contents
What is the length of the rectangle if its area is 24 cm2?
The area of a rectangle is 24 cm squared. The length is 3 cm.
What is the area of 24cm?
576 cm squared
Explanation: If each side is 24 cm, then the area would be calculated by 24⋅24 or 242 (length times base- squares are equilateral), which would be 576 . The area would be 576 cm squared.
How many rectangles of different dimensions are there which have area 24 cm square?
Six rectangles can be formed (1 , 11) , (2 , 10) , (3 , 9) , (4 , 8) , (5 , 7) , (6 , 6) with 24 cm long string.
How can I find the area of a rectangle?
Explanation: To find the area of a rectangle, multiply its width by its height. If we know two sides of the rectangle that are different lengths, then we have both the height and the width.
What is the area of the rectangle in cm²?
The area of a rectangle is 72 cm². The length of the rectangle is 6 cm longer than the width. What is the width of the rectangle? Let the width of the rectangle be x. The length of the rectangle is 6 cm longer than the width: However, the width of the rectangle cannot be a negative number, i.e. x ≠ − 12. So x = 6 is the solution to the equation.
How do you find the width of a rectangle?
Let the width of the rectangle be x. The length of the rectangle is 6 cm longer than the width: However, the width of the rectangle cannot be a negative number, i.e. x ≠ − 12. So x = 6 is the solution to the equation. Therefore, the width of the rectangle is 6 cm.
What is the distance around a rectangle called?
The distance around a rectangle is called the perimeter of the rectangle. It is usually denoted by P P. To find the perimeter of rectangle we add the lengths of its sides. Thus, the perimeter of a rectangle with the length of a a and the width of b b is
What is the formula to find the perimeter of a rectangle?
To find the perimeter of rectangle we add the lengths of its sides. Thus, the perimeter of a rectangle with the length of a a and the width of b b is P = a + b + a + b = 2 × a + 2 × b = 2 × (a + b) P = a + b + a + b = 2 × a + 2 × b = 2 × (a + b)