What is the equation of the circle with a radius of 6 units?

So, if the center is (0,0) and the radius is 6, an equation of the circle is: (x-0)2 + (y-0)2 = 62.

How do you write an equation of a circle in standard form?

The standard form of a circle’s equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius. To convert an equation to standard form, you can always complete the square separately in x and y.

What is the equation of a circle of radius 6 units centered at 3 2 )? *?

x^2+y^2–10x+6y-4.44=0 is the required equation.

How do you write the equation of a circle with the center and tangent?

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. If a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.

How do you write the equation of circle given its radius and its center at the origin What about if the center is at H k )?

The equation of a circle written in the form (x−h)2+(y−k)2=r2 where (h,k) is the center and r is the radius. The circle centered at the origin with radius 1; its equation is x2+y2=1.

How do you find the tangent of a circle with radius?

The equation for a circle is #(x-h)^2+(y-k)^2=r^2#, where #(h,k)# is the center and #r# is the radius. Since you want the circle to be tangent to the #y#-axis, and we know that tangent refers to a line that touches something at exactly one point, we want the circle to have a radius that will make it just big enough to reach the #y#-axis.

How to find the equation of a circle?

How To Find the equation of a circle given: center & tangent. This gives us the radius of the circle. Using the center point and the radius, you can find the equation of the circle using the general circle formula (x-h)* (x-h) + (y-k)* (y-k) = r*r, where (h,k) is the center of your circle and r is the radius.

How do you find the radius of a circle from a graph?

To do this, take a graph and plot the given point and the tangent on that graph. Now, from the center of the circle, measure the perpendicular distance to the tangent line. This gives us the radius of the circle.

How do you find R2 with tangent and slope?

Since the tangent touches the circle at a point where the circle has a slope of 1, we can replace y = x + 2 in the slope function and set this equal to 1, Now, since y = x +2 → y = 2 at the point of intersection. Finally, we can arrive at r2 by applying the point (0,2) to the equation of our circle.