What is the equation of a circle with center 4 3 and radius 5?

The equation of a circle that has its center at (-4, 3) and has a radius of 5 is (x + 4)2 + (y – 3)2 = 25.

Which is the equation of a circle with center (- 2 3 and radius r 5?

⇒(x−2)2+(y+3)2=25 is the equation of the circle.

What is the equation of the circle with a center of 3 and a radius of 5 units?

Explanation: The general equation for a circle is (x−h)2+(y−k)2=r2 , where (h,k) is the center and r is the radius.

What is the general equation of the circle with center 4 3 and radius 3?

The equation of the circle with center (−3,−4) and radius 3,in standard form, is: (x+3)2+(y+4)2 = 9.

What is the equation of a circle with center 3/5 and radius 6?

Solution: Given, center coordinates = (-3, -5) and radius = 6 units. r = radius of the circle. Thus the equation of the circle, can be given as (x + 3)2 + (y + 5)2 = 36.

What is the equation of a circle with center (- 2 and radius 3?

The standard form of the equation of a circle is. where (a ,b) are the coordinates of the centre and r, the radius. Substitute these values into the standard equation. ⇒(x+2)2+(y+3)2=9 is the circle’s equation.

What is the equation of the circle with centre(2 3 and radius 4)?

Ex 11.1, 2 Find the equation of the circle with centre ( 2, 3) and radius 4 We know that equation of a circle is (x h)2 + (y k)2 = r2 Where (h, k) is the centre & r is the radius Here Centre (h, k) = ( 2, 3) So h = 2 & k = 3 & radius (r) = 4.

How do you find the equation of a circle with (h)k center?

The equation of circle with (h,k) center and r radius is given by: (x-h) 2 + (y-k) 2 = r 2 Thus, if we know the coordinates of the center of the circle and its radius as well, we can easily find its equation.

How to find the radius of a circle in standard form?

Let C(h, k) be the centre of the circle and P(x, y) be any point on the circle. Therefore, the radius of a circle is CP. Let radius be ‘a’. which is called the standard form for the equation of a circle. x2 + 2gx + g2+ y2 + 2fy + f2 = g2 + f2 − c ……………… (1)

How do you find the radius of a circle with imaginary radius?

If g2 + f2 = c, then the radius of the circle is zero which tells us that the circle is a point which coincides with the centre. Such type of circle is called a point circle g2 + f2