What is the equation of a circle with a radius of 5?

The standard form of a circle is given below: (x – h)2 + (y – k)2 = r2, where the center is located at (h, k) and r is the length of the radius. In this case, h will be –3, k will be 6, and r will be 5. The answer is (x + 3)2 + (y – 6)2 = 25.

What is the equation of the circle with centre 2 3 and radius 5?

⇒(x−2)2+(y+3)2=25 is the equation of the circle.

What is the standard equation of a circle if the center is on the y axis?

The equation of a circle with centre at (h, k) and radius equal to a, is (x – h)2 + (y – k)2 = a2. When the centre of a circle is on the y-axis i.e., h = 0.

Does the point 2 StartRoot 6 EndRoot lie on the circle shown?

Does the point (2,root of 6) lie on the circle shown? Explain. No, the distance from (0, 0) to (2, root of 6) is not 3 units. Does the point (1, StartRoot 7 EndRoot) lie on the circle shown?

What is the equation of a circle with center 2 and radius 3?

Radius, r = 3 units. We have to write the equation of the circle. Therefore, the equation of the circle is (x – 2)2 + (y – 1)2 = 9.

What is the equation of the circle whose center is at the origin and whose radius is 9?

x² + y² = 81 is the equation of a circle in standard form whose center is at the origin and whose radius is 9.

How do you find the Centre and radius of a circle from an equation?

A common form to write the equation of a circle in is the center-radius form. The center-radius form is: (x−h)2+(y−k)2=r2 Here, the center point is denoted by (h,k) and r is the radius of the circle.

What is the equation of the required circle?

Thus, the required circle has its centre at (9,8) and radius =5. Hence, the equation of the required circle is (x−9) 2+(y−8) 2=5 2. Was this answer helpful?

What is the centre of the circle?

We know that equation of circle is (x – h)2 + (y – k)2 = r2 Centre of circle is denoted by (h, k) Since it lies on x-axis ]

How to find the center of a curve in Cartesian form?

Given center lies on x-axis. (x−h) 2+y 2=25 …. (1) Was this answer helpful? Express the following equation of the curve in cartesian form. If the curve is a circle find its center and radius x = 1 + t 2 a ( 1 − t 2) ​, y = 1 + t 2 2 a t ​.