Interesting

How much high above the ground a man can throw?

How much high above the ground a man can throw?

How much hight above the ground a mancan throw a ball if he is able to throw the same ball upto maximum distance of 60 m? Her, Rmax=60m. Let (h) be the maximum height attained by the ball. or h=u22g=12×60=30m.

What is the maximum vertical height to which a baseball player can throw a ball?

So, the maximum height attained by the same ball when thrown vertically upwards is 50 meters. Note: Students can get confused in understanding the question as they might assume that the question is asking to calculate the maximum height attained in the projectile motion itself.

How far can the average person throw a ball?

Assuming the first of the two the average human can throw a ball approximately 15 metres (49.213 feet) in the air. In the latter the average person could throw a ball around 60 mp/h (37.3km/h).

READ ALSO:   Which version of Hulk can defeat Thanos?

What is r in projectile motion?

The range (R) of the projectile is the horizontal distance it travels during the motion. Now, s = ut + ½ at2. Using this equation vertically, we have that a = -g (the acceleration due to gravity) and the initial velocity in the vertical direction is usina (by resolving).

What is the maximum vertical height to which a baseball player can throw a ball of his maximum throwing range is 60m?

If the distance is 60 m, the ball is released with an initial height of 16 meters. The maximum height could throw the ball.

What is the maximum vertical height to which a baseball player can throw a ball if he can throw it to a maximum horizontal distance of 100 m 1 1 2?

Vertically maximum height is reached when velocity is zero at highest point. So by using third kinematics equation v^2=u^2+2as ;we get v=0 at maximum height upwards. So h=50 m.

Can throw a ball to a maximum horizontal distance of 50 m how much high above the ground can he throw the same ball 25 m?

How high above the ground can the cricketer throw the same ball? If ball is projected vertically upwards (θ=90∘) from ground then H attains maximum value. ∴ the height to which cricketer can through the ball is =Rmax2=1002=50m.

READ ALSO:   What is a raglan cut?

What is the maximum vertical height to which a baseball player can throw a ball if he can throw it to a maximum horizontal distance of hundred Metre?

m Calculat the maximum vertcal heitht to which he can through the ball. Fiven g= 10 ms^(-2). or u2=90g=90×10=900sou=30 m//s Max. vertical height, H=u22g=9002×10=45m .

How fast can average person throw?

Without significant practice, your average person would be lucky to throw a baseball over 50 mph. For trained players, the average pitching velocity ranges between 40-50 mph among young players around 9 or 10, between 55-75 mph between 10 and 17, to an average of 80 mph for 18-year-olds and above.

How far can I throw a golf ball?

A golf ball can be thrown, on average, about 60 yards. For people who have a very strong arm and a good throwing technique, it is certainly possible for the ball to travel 100 yards or more.

What is the maximum distance a cricketer can throw the ball?

Answer Maximum horizontal distance, R = 100m The cricketer will only be able to throw the ball to the maximum horizontal distance when the angle of projection is 45∘, i.e., = 45∘. The max horizontal range for a projection velocity v is given by the relation:

READ ALSO:   Who did the dancing for John Travolta in Staying Alive?

How far can a man throw a ball?

A man can throw a ball to a maximum distance of 100m. How much high above the ground can he throw the same ball? Can your DNA tell you which foods are the best for your personal diet? I’ve heard that some DNA tests can tell you if you need high/low carbs, protein needs, etc. The short answer is yes.

When will the ball attain the maximum height from the ground?

We know that horizontal range is maximum if the angle of projection is 45o and is given by If the cricketer throws the ball vertically upwardthen the ball will attain the maximum height from the ground Hmax = u2 / 2g = 100 /2 = 50 m.

How do you find the maximum range of a ball?

Take g = 10 m/s 2 . A ball is projected from a point at two different angle with same speed u and land at the same point in the both the cases. Then A ball is projected for maximum range with speed 2 0 m s − 1.