How many ways can you arrange 3 numbers?

There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6. 720 / 6 = 120.

How many ways can you arrange 5 numbers?

120 ways
So we say that there are 5 factorial = 5! = 5x4x3x2x1 = 120 ways to arrange five objects.

How many three digit even numbers can be formed using the digits 1 to 9 without repetition?

If z is 0, then x has 9 choices. Therefore, z and x can be chosen in (1 × 9) + (4 × 8) = 41 ways. For each of these ways, y can be chosen in 8 ways. Hence, the desired number is 41 × 8 = 328 numbers 3-digit even numbers exist with no repetitions.

How many ways can the digits 0 and 1 be arranged?

Originally Answered: How many ways can the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 be arranged so that no even digit is in its original position? There are 10! ways to arrange those digits. There are 9! arrangements in which 0 retains its position.

How many numbers can be used to fill the first place?

The first blank space can be filled by 1, 2, 3, 4, 5 or 6 (having 0 as the first digit will make the number 3-digit). So 6 possibilities for first place. Now there are 6 numbers possible for second place (can include 0 now).

How many four digit numbers can be performed using each digit only?

Using digits 0,1,2,3,4,5 and 6 how many four digit numbers can be performed using each digit only once? For a 4 digit number, let’s consider 4 blank spaces. The first blank space can be filled by 1, 2, 3, 4, 5 or 6 (having 0 as the first digit will make the number 3-digit). So 6 possibilities for first place.

How many ways can you choose the second and third digit?

Choose the second digit any of 3 ways, 4,5, or 6 That leaves 5 unchosen digits Choose the third digit any of these 5 ways. Answer case 1: (1) (3) (5) = 15 ways.