How many ways can 4 consonants and 3 vowels be selected from 10 consonants and 5 vowels?
Table of Contents
- 1 How many ways can 4 consonants and 3 vowels be selected from 10 consonants and 5 vowels?
- 2 How many words of 4 consonants and 3 vowels can be formed from 6 consonants and 5 vowels?
- 3 How many words of 4 consonants and 3 vowels can be made from 12 consonants and 4 vowels if all the letters are different *?
- 4 How many words of 4 consonants and 4 vowels can be formed out of 8 vowels and 5 consonants?
- 5 How many words can be formed from 8 consonants and 5 vowels in which there are 4 consonants and 2 vowels?
- 6 How 8 consonants and 5 vowels words of three consonants and two vowels can be formed?
- 7 How many 5 letter words can be formed by taking 3 consonants and 2 vowels from the letters of the word education?
- 8 How many words of 3 consonants and 2 vowels can be formed?
- 9 How many ways can you arrange 5 letters in a sentence?
- 10 Which is the only vowel letter in the 5 letter code?
How many ways can 4 consonants and 3 vowels be selected from 10 consonants and 5 vowels?
= 120. Required number of ways = (210 x 120) = 25200.
How many words of 4 consonants and 3 vowels can be formed from 6 consonants and 5 vowels?
Answer: (2) 756000 Solution: We need to find the number of words of 4 consonants and 3 vowels from 6 consonants and 5 vowels.
How many words of 4 consonants and 3 vowels can be formed from 12 consonants and 4 vowels?
Solution(By Examveda Team) C4 ways. 3 vowels can be selected in 4C3 ways. Therefore, total number of groups each containing 4 consonants and 3 vowels, = 12C4 × 4C3 Each group contains 7 letters, which can be arranging in 7!
How many words of 4 consonants and 3 vowels can be made from 12 consonants and 4 vowels if all the letters are different *?
= 12C4 *4C3 Each group contains 7 letters, which can be arranging in 7! ways. Therefore required number of words, = 12C4 *4C3 *7!
How many words of 4 consonants and 4 vowels can be formed out of 8 vowels and 5 consonants?
Step-by-step explanation: ways, hence total number of words would be 336*5!
How many words of 4 consonants and 3 vowels can be made from 15 consonants and 5 vowels if all the letters are different?
The correct answer is (d) ^15C4 * ^5C3 * 7!
How many words can be formed from 8 consonants and 5 vowels in which there are 4 consonants and 2 vowels?
How 8 consonants and 5 vowels words of three consonants and two vowels can be formed?
Detailed Solution
- Given: Out of 8 consonants and 5 vowels, words of 3 consonants and 2 vowels to be formed.
- The concept used: Permutations and Combinations.
- Formula used: n Cr = n! /r! (n – r)!
- Calculation: Number of ways of selecting 3 consonants from 8 is 8C3 Number of ways of selecting 2 vowels from 5 is 5C2
How many words of 4 consonants and 3 vowels can be formed from 12 consonants and 4 vowels if all the letters are different?
How many 5 letter words can be formed by taking 3 consonants and 2 vowels from the letters of the word education?
Step-by-step explanation: 12*5!
How many words of 3 consonants and 2 vowels can be formed?
>> Out of 7 Consonants and 4 v… Out of 7 Consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed? = (7−3)!3!7! × (4−2)!2!4! Number of groups, each having 3 consonants and 2 vowels =210. Each group contains 5 letters. Number of ways of arranging 5 letters among themselves = 5!
What is the total number of words that can be formed?
Since the resulting word is 7 letters long, for each set of consonants and vowels, there can be 7! ways to arrange the letters to form a word. So, the total number of words that can be formed = 280 x 7! = 280 x 5040 = 1,411,200 Hope it helps..!! 8 clever moves when you have $1,000 in the bank.
How many ways can you arrange 5 letters in a sentence?
From 5 consonants, 3 consonants can be selected in 5 C 3 ways. From 4 vowels, 2 vowels can be selected in 4 C 2 ways. Now with every selection, number of ways of arranging 5 letters is 5 P 5 ways.
Which is the only vowel letter in the 5 letter code?
It is stated in the statement that the middle letter is the only vowel letter. Also, there has to be 2 vowels in the 5 letter code. The conditions are contradictory hence no word cannot be created.