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How many ways can 4 consonants and 3 vowels be selected from 10 consonants and 5 vowels?

How many ways can 4 consonants and 3 vowels be selected from 10 consonants and 5 vowels?

= 120. Required number of ways = (210 x 120) = 25200.

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How many words of 4 consonants and 3 vowels can be formed from 6 consonants and 5 vowels?

Answer: (2) 756000 Solution: We need to find the number of words of 4 consonants and 3 vowels from 6 consonants and 5 vowels.

How many words of 4 consonants and 3 vowels can be formed from 12 consonants and 4 vowels?

Solution(By Examveda Team) C4 ways. 3 vowels can be selected in 4C3 ways. Therefore, total number of groups each containing 4 consonants and 3 vowels, = 12C4 × 4C3 Each group contains 7 letters, which can be arranging in 7!

How many words of 4 consonants and 3 vowels can be made from 12 consonants and 4 vowels if all the letters are different *?

= 12C4 *4C3 Each group contains 7 letters, which can be arranging in 7! ways. Therefore required number of words, = 12C4 *4C3 *7!

How many words of 4 consonants and 4 vowels can be formed out of 8 vowels and 5 consonants?

Step-by-step explanation: ways, hence total number of words would be 336*5!

How many words of 4 consonants and 3 vowels can be made from 15 consonants and 5 vowels if all the letters are different?

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The correct answer is (d) ^15C4 * ^5C3 * 7!

How many words can be formed from 8 consonants and 5 vowels in which there are 4 consonants and 2 vowels?

How 8 consonants and 5 vowels words of three consonants and two vowels can be formed?

Detailed Solution

  • Given: Out of 8 consonants and 5 vowels, words of 3 consonants and 2 vowels to be formed.
  • The concept used: Permutations and Combinations.
  • Formula used: n Cr = n! /r! (n – r)!
  • Calculation: Number of ways of selecting 3 consonants from 8 is 8C3 Number of ways of selecting 2 vowels from 5 is 5C2

How many words of 4 consonants and 3 vowels can be formed from 12 consonants and 4 vowels if all the letters are different?

How many 5 letter words can be formed by taking 3 consonants and 2 vowels from the letters of the word education?

Step-by-step explanation: 12*5!

How many words of 3 consonants and 2 vowels can be formed?

>> Out of 7 Consonants and 4 v… Out of 7 Consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed? = (7−3)!3!7! × (4−2)!2!4! Number of groups, each having 3 consonants and 2 vowels =210. Each group contains 5 letters. Number of ways of arranging 5 letters among themselves = 5!

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What is the total number of words that can be formed?

Since the resulting word is 7 letters long, for each set of consonants and vowels, there can be 7! ways to arrange the letters to form a word. So, the total number of words that can be formed = 280 x 7! = 280 x 5040 = 1,411,200 Hope it helps..!! 8 clever moves when you have $1,000 in the bank.

How many ways can you arrange 5 letters in a sentence?

From 5 consonants, 3 consonants can be selected in 5 C 3 ways. From 4 vowels, 2 vowels can be selected in 4 C 2 ways. Now with every selection, number of ways of arranging 5 letters is 5 P 5 ways.

Which is the only vowel letter in the 5 letter code?

It is stated in the statement that the middle letter is the only vowel letter. Also, there has to be 2 vowels in the 5 letter code. The conditions are contradictory hence no word cannot be created.