How many three digit numbers can be formed with the digits 1 2 5 4 6 The elements are repeated?

Problem 2: How many 3-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated? Solution: Answer: 108. Let 3-digit number be XYZ.

How many 6 digit numbers can be formed without repeating?

The answer is 600.

How many even numbers are more than 5000?

It is common to know that all 5-digit numbers are greater than 5000, so we only got to consider the even 5-digit numbers that can be made with these numbers. All in all 102 numbers(4-digits and 5-digits) can be made which are greater than 5000 and also even.

How many different three digit numbers can be formed using the integers 1 to 6 if no integer occurs twice in a number?

The answer is 53,040.

How many numbers greater than 5000 can be formed using the digits 3 4 5 6 and 7 without repetition of digits how many of these are even?

The number of 4 digit numbers greater than 5000 can be formed out of the digits 3,4,5,6 and 7(no. digit is repeated). The number of such is. 72.

How many 4 digit numbers that can be formed from the digits 2 3 5 6 7 and 9 which are divisible by 5 and none of the digits is repeated?

∴ 60 four-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9.

Which of the following numbers is not an integer?

The numbers such as 8.5, 2 3 and 4 1 3 are not integers. (Note that a number can be an integer even if it is written as a decimal or a fraction: for example, − 3.00 and 8 2 are both integers, because they are equal to − 3 and 4, respectively.) The set of integers is usually represented by the symbol ℤ.

How many three digit numbers can be formed from 6x5x4=120?

The first digit can be any one of the 6 digits given, The second must be different so only 5 are allowed. And the third must be different from the first two so only 4 are allowed. Thus, there will be 6x5x4=120 three digit number formed from the numbers 1, 2, 3, 4, 5, and 6 if no repitions of digits aea allowed

How many numbers can be formed using one digit only?

I am assuming that you mean how many 1,2 or 3 digit positive integers can be formed using the integers 1,2,3,4,5,6 without using any of these more than once. In that case, the answer is 156. There are clearly 6 numbers using one digit only.

How do you solve for even numbers with all 7 digits?

If we assume each number has to use all 7 digits, then the solution would be trivial. The last digit of each number must be one of 2, 4, or 6 in order to be even. The rest of the 6 digits can be in any order. Thus the solution would be , which equates to 2160.