How many three digit numbers are divisible by 7 and leaves remainder 5?

Thus, 105, 112, 119, is forming an A.P. having the first term as 105 and a common difference of 7. When we divide 999 by 7, the remainder will be 5. Clearly, 999 − 5 = 994 is the maximum possible three-digit number that is divisible by 7.

What is the largest 3 digit number when divided by 7 leaves a remainder of 4 and when divided by 9 leaves a remainder of 3?

For the part (b) we will add 4 to 900 which gives 904. And we know that 900 is divisible by 75, 45, 60 so, 904 will give us the required remainder 4 when divided by each number. Hence, 904 is the correct answer for (b).

How many three digit numbers are such that when divided by 7 leave a remainder three in each case?

Hence, 129 number are divided by 7 which leaves remainder is 3.

Which is the greatest 3 digit number which when divided by 6 9 and 12 leaves a remainder of 3 in each case?

Step-by-step explanation: First we find LCM of 6 , 9 & 12 then we find multiple of LCM to obtain largest 3-Digit Number. Multiple of 36 = 36, 72, 108, 144, 180, 216, 252, 288, 324, 360, 396, 432, 468, 504, 540, 576, 612, 648, 684, 720, 756, 792, 828, 864, 900, 936, 972, 1008, Therefore, Required Number is 975.

Which is the largest 3 digit number which when divided by 5 and 7 leaves remainder 3 and 2 respectively?

The answer is 983. Refer to the attachment for step by step explanation.

How many 3-digit numbers are there which are divisible by 7?

128 3-digits
∴ There are 128 3-digits number which are divisible by 7.

How many three digit number are there which are divisible by 7?

128 three digit numbers
Hence, 128 three digit numbers are divisible by 7.

What are the remainders for division by 2 3 3 5?

The remainders for the division by 2, 3, 5 can be considered as − 1 and any multiple of L.C.M. of these numbers − 1 will satisfy the condition. The 3 digit numbers from 100 to 999 have a stretch of 900 and can contain 4 spans of 210, making way to 5 eligible numbers.

What are the three digit numbers which upon division give 5?

The three digit numbers which upon division by 3, 5 and 7, give remainder of 5 are 110, 215, 320, 425, 530, 635, 740, 845 and 950. Let x be a three digit number satisfying the conditions stated in the problem.

What is the remainder when 599 is divided by 9?

What is the remainder when 599 is divided by 9? The remainder is 5 . To calculate this, first divide 599 by 9 to get the largest multiple of 9 before 599. 5/9 < 1, so carry the 5 to the tens, 59/9 = 6 r 5, so carry the 5 to the digits. 59/9 = 6 r 5 again, so the largest multiple is 66.

How many three digit numbers are divisible by 7?

– Maths Q&A How many three digit number are divisible by 7? ∴ There are 128 3-digits number which are divisible by 7. Was this answer helpful? Thank you.

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