How many solutions are there of the equation a/b/c d 100?

The answer is 784.

How many different whole number solutions are there to the equation a/b/c 10?

such ordered positive integer solutions of the equation a+b+c=10. We count each unordered solution of this type three times, depending on where the single number is located. That leaves 36−12=24 solutions of the equation a+b+c=10 in which all three numbers are distinct.

How many solutions does the equation a/b/c d 20 have where A B C D are non negative integers?

Total number of non-negative integers (a,b,c,d) is number of such (a,b) + (c,d) which is 155 +210 = 365. Therefore the total number of unique non-negative integers (a,b,c,d) such that a+b+c+d = 20 and a>b is 365.

How many solutions are possible for the equation a/b c?

If a,b, and c are any real number then there are infinitely many solutions, but if a, b, and c are non negative integers then the number solutions can be find by Brute force method. For x^2 – y^2 = 350, (x+y)(x-y)=350.

How many non negative integer solutions are there?

Total no. Of non negative solutions are 10.

How many solutions does this system of equations have?

A system of two equations can be classified as follows: If the slopes are the same but the y-intercepts are different, the system has no solution. If the slopes are different, the system has one solution. If the slopes are the same and the y-intercepts are the same, the system has infinitely many solutions.

How many positive integer solutions are there for x + y + z+w?

Your equation is x + y + z + w = ( x + y) + ( z + w) = 15. First we see x + y and z + w as two unknowns, that is a + b = 15 and a, b satisfy 2 ≤ a, b ≤ 13. Easily, we can say that there are 12 positive integer solutions for a and b.

How many non-negative integer solutions are there to M + N + O+P?

From your attempt we know that this problem is equivalent to the number of non-negative integer solutions to m + n + o + p = 11, which is far simpler. This type of problem is sometimes known as “Stars and Bars” http://en.wikipedia.org/wiki/Stars_and_bars_\%28combinatorics\%29.

What is the total number of solutions for x = 100 – 3Y?

For x, to be integer (100 – 3y) must be an even number so that it becomes divisible by 2. Since 100 is even , 3y must be even number. y< 33 and y should be even. y= [0,2,4,…32] . Since 0 is not a positive number. Hence, it is excluded. Therefore, Total number of solutions is 16. Hope that helps. 🙂 , Works as a Student and a Quoran.

Which integer values of X would satisfy the equation?

The integer values of x that would satisfy the equation will be in an Arithmetic Progression where the common difference is the co-efficient of y and vice-versa. Now, the other integer values of x would be 53, 56, 59,.. and also in the other direction like 47, 44, 41, 38…. and so on.