How many numbers can be formed which are divisible by 5 and less than 1000?

Condition 1: For a number to be divisible by 5, its unit digit must be “0” or “5”. Now, for all natural numbers from 1 to 999 (because the question says less than 1000), 199 natural numbers satisfy this.

How many numbers less than 1000 and divisible by 5 can be formed in which no digit occurs more than once?

Number of natural numbers less than 1000 and divisible by 5 can be formed with the ten digits, each digit not occuring more than once in each number is. at ones place there can only 2 numbers=5,0 which are divisible by 5. at hundred place there can be 9 numbers.

How many numbers less than 1000 are multiple of both 10 and 13?

Description for Correct answer: Take LCM of 10 and 13 = 130 Any no. divisible by 130 will be divisible by 13 and 10.

How many numbers between 400 and 1000 can be formed with the digits?

So, the required number of numbers is 60.

What is the number of numbers less than 1000 and divisible by 5 which can be formed with digits 0 to 9 such that no digit gets repeated?

If the last digit is 0, then the number of ways for the first digit = 9 and for the 2nd digit it will be 8 ways. If the last digit is 5, then the number of ways for the 1st digit = 8 and for the 2nd digit is 8 as this time 0 can be placed in the 2nd digit. Thus, Total number of numbers = 1 + 17 + 136 = 154 ways.

How many 3 digit numbers are divisible by 3 can be formed?

300 3-digit numbers divisible by 3. so there is an A.P. whose common difference is 3 and where the first number (i.e. a=102) and the n number is 999. ⟹ n = 300 , thus there are 300 three digit number s which are divisible by 3…

How many 3 digits number can be formed from the digits 2 3 5 6 7 and 9 which are divisible by 5 and none of the digits are repeated?

There is 5 possible ways to fill ten’s place. There is 4 possible ways to fill hundredth place as digits cannot be repeated. ∴ 3 – digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 is 20.

What number is divisible by 5 but not by 8?

Since the given number is divisible by 5, 0 or 5 must come in place of $. But a number ending with 5 is never divisible with 8 because a divisible number must be even. Therefore 0 will replace $. If the number is divisible by 8, the number formed by last three digits must be divisible by 8.

How to print all the factors that are divisible by 3/5?

Using a loop with & (and) operator statement (so that it print only those numbers which are divisble by both 3 & 5), prints all the factors which is divisible by the number. Exit.

What if last 2 digits are divisible by 4?

If last 2 digits are divisible by 4, then number is also divisible by 4. What should be the value of * in 985*865, if number is divisible by 9?

How many numbers between 100-195 have repetitive digits?

Since 1-digit number cannot have repetitive digits. 2-digit numbers divisible by 5 are 10,15,20,25,…,50,55,60,…95. Only 55 has repetitive digits. You can see that there are exactly 4 numbers between 100-195 which have repetitive digits.