How many different committees can be selected from 8 men and 10 women if a committee is composed of 3 men and 3 women?
How many different committees can be selected from 8 men and 10 women if a committee is composed of 3 men and 3 women?
There are 10 possible values for each digit of the PIN (namely: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9), so there are 10 · 10 · 10 · 10 = 104 = 10,000 total possible PIN numbers. To have no repeated digits, all four digits would have to be different, which is selecting without replacement.
How many ways can five persons be selected to form a committee so that at least 3 men are there in the committee given that there are 7 men and 6 women?
Thus, the number of ways to select a 5-person committee with at least 3 men is:525 + 210 + 21 = 756. answer : 756 ways .
How many men and women are needed to form a committee?
A committee of 5 is to be formed from 8 women and 12 men. How many committees are possible if there must be 3 women and 2 men? – Quora A committee of 5 is to be formed from 8 women and 12 men. How many committees are possible if there must be 3 women and 2 men? 8 clever moves when you have $1,000 in the bank.
How many members can a committee of 5 members have?
Originally Answered: A committee of 5 members is to be chosen from 12 men and 8 women and is to consist of 3 men and 2 women. How many such committee can be formed? A committee of 5 members is to be chosen from 12 men and 8 women and is to consist of 3 men and 2 women.
How many different types of committees are there?
There are 1,176 different possible committees. Let’s break this down into the two sub-groups: one with men, and one with women. Of the 8 men available, we must choose 3. The number of possible groups is 8C3, which is 8! 3! × 5! = 56. Of the 7 women available, we must choose 2. The number of possible groups is 7C2, which is 7! 2! × 5! = 21.
How many possible combinations are there with 56 men and 15 women?
Well, you can form 8 choose 3 groups of men, and for each of those you can choose any of the 6 choose 2 groups of women. nCr=n!/ ( (r!) (n−r)!) So, 56*15=840 possible combinations, assuming you don’t care about anything other than number of men, number of women.