How many 2 digit numbers are there having exactly 6 factors?
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How many 2 digit numbers are there having exactly 6 factors?
15, i believe, is the answer. In general, a² * b will have (2+1)(1+1)= 3*2 =6 factors (three choices for a power of a and two choices for b in a particular factor). Also,this limits the number of factors that we can have in such a number.
What is a 2 digit multiple of 8?
The answer is 64. To be a multiple of 8 , the number must be 64. where is an integer. So the only two-digit number that conforms to the conditions is 64.
What is the smallest number that has exactly 8 factors?
24
Therefore, smallest number that has exactly 8 factors = 24.
What multiple of 8 is also a factor of 8?
Thus, as per the definition given above, the multiple of 8 is obtained by multiplying some integer with 8. For example, 48, 56, 64 and 96 are all multiples of 8 for the following reasons….8, 16, 24, 32,….., 72, 80, 88,….
| 8 × 6 = 48 | 8 multiplied by 6 to get 48 |
|---|---|
| 8 × 12 = 96 | 8 multiplied by 12 to get 96 |
How do you find multiples of 8?
Multiples of 8 by Multiplication Multiples of 8 will be the product of 8 with any natural number i.e 8n, where n is any natural number. So, the pattern formed is: 8, 24, 40, 56, 72, 88, 104.
How many two-digit numbers have exactly 12 factors?
So, there are 5 two digit numbers which have 12 factors. They are 60, 72, 84, 90, 96 Hence there are 5 two digit numbers having exactly 12 factors – 60,72,84,90,96. 8 clever moves when you have $1,000 in the bank.
How many factors does a² * B have?
In general, a² * b will have (2+1) (1+1)= 3*2 =6 factors (three choices for a power of a and two choices for b in a particular factor). Also,this limits the number of factors that we can have in such a number.
How do you find the number of factors of N?
The number of factors of n, as we discussed many times on Quora, is simply ( e 1 + 1) ( e 2 + 1) ⋯ ( e k + 1). This is because any factor of n must use each prime at most as many times as n does. Otherwise, you’re free to choose the exponents of each prime p i in such a factor, anywhere from 0 to the max value of e i.
How many two digit numbers can be split 12?
We are given number of factors = 12. => (p + 1)*(q + 1)*(r + 1)…. = 12. So, the possibilities for splitting 12 are 12, 2*6, 3*4, 2*2*3. So, the number could be of the format a^11, a*b^5, a^2*b^3, a*b*c^2. a^11 format – No two digit number possible.