How long is a ball in contact with the ground?
Table of Contents
How long is a ball in contact with the ground?
The answer is 0.341 seconds.It can be wrong.
What is the maximum height of the ball?
Question: A ball thrown vertically upward reaches a maximum height of 30 meters above the surface of Earth. At its maximum height, the speed of the ball is: Answer: 0 m/s. The instantaneous speed of any projectile at its maximum height is zero….Objects Launched Upward.
| Variable | Value |
|---|---|
| v | 0 m/s |
| Δy | FIND |
| a | -9.8 m/s2 |
| t | 0.40 s |
How is dropping of a ball from a given height is an example of conservation of energy?
The Law of Conservation of Energy states that energy cannot be created or destroyed, but can be transformed. In Ball Drop, we see energy being transformed, although the total amount of energy re- mains the same.
What is the average acceleration of a basketball when it is dropped?
A ball is dropped on the floor from a height of 10 m. It rebounds to a height of 2.5 m.If the ball is in contact with the floor for 0.01 sec, then average acceleration during contact is A 2100m/s2
When a ball is dropped from a height of 10m?
Originally Answered: A ball is dropped from a height of 10m . it loses 10 \% of its initial energy due to air resistance and 10\% when the ball comes in contact with th e ground. till what height will the ball bounce back again? The ball falling from the height of 10 meters, means initially it is having 100 percent of energy due to its height.
What is the speed of the ball when it hits the floor?
Since the ball falls from a height of 5m, its speed at the time of striking the concrete floor, can be obtained using the relation v² – u² = 2 g h. In our case u = 0 m/s as it is just dropped; h = 5 m; g = 10 m/s². So v² = 2× 10×5 = 100 (m/s)² or v = 10 m/s.
Is the force acting on a tennis ball constant?
In reality the force acting on the tennis ball isn’t constant. The force is a function of the tennis ball deformation during the ball contact with the floor, F = k*Δx. The tennis ball acceleration is approximately a = Δv/Δt = 16.52/0.01 = 1652 m/s². I calculated the acceleration assuming that the force acting on the ball is constant.