How do you solve XY 6?

1. xy=6. xy=6. The equation is in standard form. The equation is in standard form.
2. xy=6. xy=6. Divide both sides by x. Divide both sides by x.
3. \frac{xy}{x}=\frac{6}{x} xxy​=x6​ Dividing by x undoes the multiplication by x. Dividing by x undoes the multiplication by x.

What is the solution of the equation x/y 6 XY 2?

Hence, x = 4, y = 2 is the solution of the given system of equations.

Is xy 6 standard form?

Explanation: Standard form for a linear equation is Ax+By=C . y−6=0 in standard form would be y=6 .

What is the solution to this system of linear equations y x 6 y x 10?

(-8, -2)
The solution to this system of linear equations y – x = 6, y + x = – 10 is (-8, -2).

What type of lines are represented by the equations 6x 3y 10 0 and 2x y 9 0?

Hence, the pair of equations represents two parallel lines.

What are the y-terms of X and Y?

The y-terms are additive inverses which means they add to zero. x = 3 and y = 1 Explanation: This is the best scenario you can get with a system of equations. The y-terms are additive inverses which means they add to zero.

What is an example of a system of simultaneous equations?

An example of a system of simultaneous equations is: x + y = − 1 3 = y − 2 x We have two independent equations to solve for two unknown variables. We can solve simultaneous equations algebraically using substitution and elimination methods.

What is X in the middle of 6 and 10?

First, you know that the distance from 6, x, and 10 are equal, so that means that x is in the middle of 6 and 10, meaning that x is 8. Now to get y, you have to subtract x from 10, which results in y being 2. Answer:- (x, y) = (8, 2).

How do you subtract an equation from another equation?

Substitute value of \\ (x\\) into second equation: Substitute value of \\ (y\\) back into first equation: Therefore \\ (x =11 ext { and } y = 5\\). If we multiply the first equation by 2 then the coefficient of \\ (y\\) will be the same in both equations: Now we can subtract the second equation from the first: