How do you find the dimensions of a rectangle given the area and perimeter?
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How do you find the dimensions of a rectangle given the area and perimeter?
Find the dimensions of a rectangle with perimeter 100 m whose area is as large as possible.
- Explanation: Let ‘A’ be area and ‘P’ be perimeter of the rectangle. Let ‘x’ be the width and ‘y’ be the length.
- Perimeter = 2 (length + breadth) Hence, P = 2(x+y)
- Area of a rectangle = Length × Breadth. Hence,
How do you find the width of a perimeter?
Explanation: To find the width, multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width.
How to calculate the length and width of a rectangle?
Online calculator to calculate the dimensions (length and width) of a rectangle given the area A and perimeter P of the rectangle. The formulas for the perimeter P and the area A of the rectangle are used to write equations as follows: P = 2 * L + 2 * W A = L * W
What is the length of the rectangle with the perimeter 66?
The length of a rectangle is 7 inches more than its width. If the perimeter of the rectangle is 66, what are its dimensions? Let “n” be the width. Then “n+7” is the length. perimeter is twice the length plus twice the width. n+7 = 20. The width is 13 inches. The length is 20 inches.
What is the formula to find the area of a rectangle?
A = length × width = a × b A = length × width = a × b. In other words, the area of a rectangle is the product of its length and width. The perimeter is measured in units such as centimeters, meters, kilometers, inches, feet, yards, and miles.
What are the outputs of the rectangle problem?
The outputs are the width, length and diagonal of the rectangle. There are conditions under which this problem has a solution (see formulation of problem below). Let P be the perimeter of a rectangle and A its area. Let W and L be, respectively, the width and length of the rectangle.