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What is the time period of a geostationary satellite?

What is the time period of a geostationary satellite?

Geostationary satellite is one of the artificial satellites, which revolves around Earth’s equator above 22,236 miles in a geostationary orbit. It has an orbital period equal to Earth’s rotational period of 23 hours and 56 minutes, which is about one day on earth.

What is the height of geostationary satellite?

35,786 km
1.2. 1 Geostationary Satellites. A geostationary satellite is in a geostationary orbit, which can only be achieved at an altitude very close to 35,786 km (22,236 m) and keeps the satellite fixed over one longitude at the equator. The satellite appears motionless at a fixed position in the sky to ground observers.

What is the period of a geostationary satellite in seconds?

Given that a geostationary satellite is, by definition, stationed over a single point on the Earth’s surface, its period is exactly that of the Earth’s. That’s to say, a geostationary satellite’s period is presently 23 hours, 56 minutes and four seconds, give or take small errors.

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What is distance and height of geostationary orbit?

A geosynchronous orbit is a high Earth orbit that allows satellites to match Earth’s rotation. Located at 22,236 miles (35,786 kilometers) above Earth’s equator, this position is a valuable spot for monitoring weather, communications and surveillance.

What is the height of satellite?

The height of geostationary satellite from the surface of the earth is 36000 km.

The time period of a geostationary satellite is 24 h, at a height 6RE (Re is radius of Earth) from surface of Earth. The time period of another satellite whose height is 2.5 RE from surface will be, [NEET (Odisha) 2019]

What is the velocity of a geostationary orbit around the Earth?

A geostationary orbit can only be achieved at an altitude very close to 35,786 km (22,236mi), and directly above the Equator. This equates to an orbital velocity of 3.07km/s(1.91mi/s) or an orbital period of 1,436 minutes, which equates to almost exactly one sidereal day or 23.934461223 hours, which is approximately 24 hours.

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What is a geo-stationary satellite?

A geo-stationary satellite is a geo-synchronous satellite that is placed in equatorial orbit. Time required for 1 revolution = approximately 24 hours (exactly 23.9344 hours or 1436. 064 minutes), which equates to almost one sidereal day .

How do satellites appear to be fixed on the Earth?

For a satellite to appear fixed at a position above a certain place on the Earth, its orbital period around the Earth must be exactly equal to the rotational period of the Earth about its axis. Consider a satellite of mass m moving in a circular orbit around the Earth at a distance r from the centre of the Earth.