How many ways can 5 men and 5 women sit in a row if no 2 men sit next to eachother?

Then count ways to put the five distinct males and five distinct females in each from these arrangements of places. Thus the answer of 86,400 is obtained.

How many different ways can 5 people be arranged to sit around on a circular table so that 2 people must sit together?

24
Circular Permutations: The number of permutations of n elements in a circle is (n − 1)! In how many different ways can five people be seated at a circular table? So the answer is 24.

How many ways can 5 men and 4 women?

(which is 5P5). Now, combining these results, we have a total number of combinations of 4! ×5!= 2880.

How many ways can six people be seated around a circular table if two of them insist on being seated together?

Example 1 In how many ways can 6 people be seated at a round table? Solution As discussed in the lesson, the number of ways will be (6 – 1)!, or 120. (i) A and B always sit together.

How many ways can 5 men?

Now, 5 men can sit in a round table in (5–1)!= 24 ways.

How many different ways can 5 people be arranged?

Answer: If the symmetry of the table is not taken into account the number of possibilities is 5! = 120. In this case it would be the same as ordering people on a line. However if rotation symmetry is taken into account, there are five ways for people to sit at the table which are just rotations of each other.

How many ways can 5 person occupy 3 seats?

Therefore, the number of possible solutions is 60.

How many ways can 3 people be seated?

So there are two answers: There are 3! = 6 different ways of placing these three people in three distinct chairs. However, it we decide to consider rotated arrangements as basically the same, then there are only 2 ways.

How many ways can 6 people be seated at a round table?

Find the number of ways in which 6 persons out of 5 men and 5 women can be seated at a round table such that 2 men are never together. 6 people may be 3 men and 3 women, 2 men and 4 women or 1 man and 5 women. Then by the gap method, 3 men and 3 women can be seated in ( 5 3) 2! 3! = 120 ways.

How many seats are required to seat 5 men and 4 women?

Misc 9 It is required to seat 5 men and 4 women in a row so that the women occupy the even places. How many such arrangements are possible? There are total 9 people Since women occupy even places Places 2, 4, 6, 8 will be occupied by women And Rest will be occupied by men The seating ar

How many ways can 5 men and 5 women sit together?

Since there are 5 men, there will be 5 gaps where 5 women can sit in 5!=120 ways. Hence, total number of arrangements of sitting of 5 men and 5 women with no two women can sit together is 24*120= 2880. Early symptoms of spinal muscular atrophy may surprise you.

How many ways can the three women be arranged among themselves?

The three woman can be arranged among themselves in 3! ways. According to Fundamental principle of counting, Total No of ways in which 4 men & 3 women can be seated around a round table such that women always sit together is 4! x 3! = 144 ways Since all women sit together, let us treat them as a single unit.