How many 5 digit number can be made which are divisible by 3 Using digit 0 to 6?

The answer is 3,240. The answer is 3,240. 100000 100020 100040 100100 100120 100140 100200 100220 100240 100300 100320 100340 100400 100420 100440 100500 100520 100540 101000 101020 101040 101100 101120 101140 101200 101220 101240 101300 101320 101340 …

How many five digit positive integers that are divisible by 3 can be formed?

How many five digit positive integers that are divisible by 3 can be formed using the digits 0, 1, 2, 3, 4 and 5, without any of the digits getting repeating? but this is not the answer? the correct answer is 216.

How many 5-digit numbers can be formed using (0-9)?

How many 5-digit numbers can be formed using (0-9)? You can have up to 10 combinations for each digit, times the number of… Numbers you want. The trick is to realize that a number can not start with a zero! Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number.

What is the total number of choices for the first digit?

For the third number, there are 4 choices, for the fourth number there are 3 choices, and for the fifth number there are 2 choices. Thus, the total number of choices is (5) (5) (4) (3) (2) = 600. Alternatively, use the same logic and realize there are 5 choices for the first digit.

How many combinations can you have for a 5 digit number?

You can have up to 10 combinations for each digit, times the number of… Numbers you want. The trick is to realize that a number can not start with a zero! Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number.

What is the first and second digit of a 5 digit number?

For the first digit, there are only five options (5, 6, 7, 8, and 9) because a five-digit number must start with a non-zero integer. For the second digit, there are 5 choices again, because now zero can be used but one of the other numbers has already been used, and numbers cannot be repeated.