How many 5 digit numbers formed using the digits 0 1 2 3 4 5 are divisible by 3 if the digits are not repeated?

Since, repetition is not allowed, for the next significant place, 4 digits are available (since 0 can now be used). Sum of the digits = 0 + 1 + 2 + 3 + 4 = 10 which is not divisible by 3. ∴ None of the 5-digit numbers formed using the digits 0, 1, 2, 3, and 4 will not be divisible by 3.

How many 5 digit number formed using the digits 0 1,2 3 4 5 are divisible by 5 if the digits are not repeated?

If 0 is the first digit, then number of places left to be filled is 4 and that can be done in 4! ways. So, the 5 digits numbers that can be formed which ends with is 120 – 4! = 96.

How many 3 digit numbers can be formed using the digits 0?

Originally Answered: How many 3 digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 if repetitions of digits are not allowed? There are nine possible first digits, because numbers beginning in 0 drop the 0, so 012 is really just 12, a two digit number. The first digit must be 1 thru 9, nine possible digits.

How to write all possible 2-digit numbers?

Write all possible 2-digit numbers that can be formed by using the digit 3, 7 and 9. Repetition of digits is allowed.

How do you choose the first two digits of 012?

There are nine possible first digits, because numbers beginning in 0 drop the 0, so 012 is really just 12, a two digit number. The first digit must be 1 thru 9, nine possible digits. The second digit can be any of the nine digits left after you take the first digit out of the pool of choices. So 9*9 ways to chose the first two digits.

How many unchosen digits are there between 330 and 400?

Case 1: All those between 330 and 400 Choose the first digit 1 way (as 3) That leaves 6 unchosen digits. Choose the second digit any of 3 ways, 4,5, or 6 That leaves 5 unchosen digits Choose the third digit any of these 5 ways.