What is the equation of straight line passing through the point of intersection?

x+y+3=0.

How do you find the equation of a line passing through a point and is perpendicular?

Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. Thus, the equation of the line is y = ½x + 6. Rearranged, it is –x/2 + y = 6.

What is the equation of the straight line passing through the point 2 3?

these lines pass through (2,3) Thus, ci = 2 and 6 + 12 =c=18 Therefore, lines are x = 2 and 3x + 4y – 18 = 0.

Are slopes of parallel lines related?

In other words, the slopes of parallel lines are equal. Note that two lines are parallel if their slopes are equal and they have different y-intercepts. In other words, perpendicular slopes are negative reciprocals of each other.

How many number of straight lines perpendicular to the line 2x 3y 6 0 are?

Answer: There can be infinite number of lines perpendicular to the line of this equation.

Which of the following is the equation of a straight line?

The general equation of a straight line is y = mx + c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis.

Which one of the following lines passes through the origin?

Any line passing through origin is of the form y = mx or ax + by = 0. Here in the given option, 2x – y = 0 is in the form ax + by = 0.

How do you find the equation of a straight line?

Find the equation of a straight line through the intersection of lines 7x + 3y = 10, 5x − 4y = 1 and parallel to the line 13x + 5y +12 = 0 First, let us find the point of intersection of the given lines 7x + 3y = 10, 5x − 4y = 1. The required line is passing through the point (1, 1) and parallel to the line 13x + 5y + 12 = 0

Which equation represents a straight line passing through the origin?

In general, therefore, the equation y = mx represents a straight line passing through the origin with gradient m. Key Point The equation of a straight line with gradient m passing through the origin is given by y = mx.

How do you find the intercept of a straight line?

The general equation of a straight line is y = mx+c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercepton the y-axis.

What is the equation of a straight line with gradient m?

The general equation of a straight line is y = mx+c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercepton the y-axis. Key Point The equation of a straight line with gradient m and intercept c on the y-axis is y = mx+c. www.mathcentre.ac.uk 5 c mathcentre 2009