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When a body dropped from a height?

When a body dropped from a height?

A body dropped from a height h with initial velocity zero, strikes the ground with a velocity 3m/s. Another body of same mass dropped from the same height h with an initial velocity of 4m/s. The final velocity of second mass, with which it strikes the ground is.

When a body is dropped from a height What is its initial velocity Class 9?

Initial velocity of a body when dropped from a height is zero, i.e., u=0.

When a body is dropped freely it falls with an acceleration?

A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth).

When a body is dropped freely from a height its initial velocity is?

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When a body is dropped freely from a height, its initial velocity (u) is zero.

When a body is dropped from a height What is it’s initial velocity *?

What is the formula for distance traveled when a body is dropped?

Assume the bodies are dropped from sufficiently tall tower that it takes longer than 5 seconds to reach the ground. Formula for distance traveled for a body dropped from a height = (1/2)*acceleration due to gravity * (time squared) Acceleration due to gravity =9.8m/Sec squared. Is a constant.

Why is the relative displacement of 2 bodies equal to 0?

Because both of the masses are dropped so Therefore u=0 for both the masses. And also a=-g. Now you will get displacement for both the bodies subtract displacement of body 2 from displacement of body 1 you will get relative displacement of body 2 w.r.t body 1 i.e the separation between them.

What is the initial velocity of a ball dropped from height?

Since a ball is dropped from certain height the initial velocity is going to be zero. And acceleration is nothig but acceleration due to gravity. And distance ‘s ‘ is nothing but height. Initial velocity=0. acceleration=9.8 height=10 we use formula. v^2 =u^2+2as =>. v^2=2as =>. v=√2as=>. V=√2×9.8×10=> V=14 Answer

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What is the potential energy and acceleration of a dropped ball?

So therefore potential energy of the ball must be equal to kinetic energy of the falling body. so v is equal to sqrt 2 gh. So answer is 14.14 m/s. Since it is dropped it’s initial velocity must be zero. And acceleration is acceleration due to gravity that is 9.8m/s^s.