What is the height of the ball after the first bounce?

The maximum height it reaches after its first bounce is 70 percent of 200 feet, or 140 feet. After the second bounce, it reaches a height of 70 percent of 140 feet, or 98 feet. In similar fashion, the ball continues to rebound to a height that is 70 percent of the highest point of the previous bounce.

How do you find velocity after bounce?

3 Answers

1. While the ball is not in contact with the ground, the height at time t after the last bounce at t0 is given by h(t+t0)=v0t−12gt2. where v0 is the velocity just after the bounce.
2. During the impact, the ball will deform and there will be friction.

When a ball bounces it rises to 34 of the height from which it fell If the ball is dropped from a height of 32 m How high will it rise at the third bounce?

Answer: The ball will bounce 13.5 m at the third bounce.

How does drop height affect bounce height?

If the drop height increases, then the resulting bounce height will also increase, because as the drop height increases, so does the gravitational potential energy which can be converted back into kinetic energy on the rebound.

How Does height affect bounce height?

What is the relationship between drop height and bounce height?

The relationship between drop height and bounce height is only linear for small drop heights. Once a ball reaches a certain height, the bounce height will begin to level off because the ball will reach its terminal velocity.

What is the total vertical distance of the ball when dropped?

After the ball is dropped the initial 3 m, it bounces up and down a distance of 2.4 m. Each bounce after the first bounce, the ball travels 0.8 times the previous height twice — once upwards and once downwards. So, the total vertical distance is given by h =3+2 (2.4+ (2.4×0.8)+ (2.4×0.8 2)+…)=3+2×1

What is the height of the ball after each bounce?

1. A ball is dropped from a height of 10 feet and bounces. Each bounce is [3/4] of the height of the bounce before. Thus after the ball hits the floor for the first time, the ball rises to a height of 10 ( [3/4]) = 7.5 feet, and after the it hits the floor for the second time, the ball rises to a height of 7.5 ( [3/4]) = 10 ( [3/4]) 2 = 5.625 feet.

How much energy does a ball lose when dropped from 10m?

A ball is dropped from a height of 10m. It loses 10 \% of its initial energy due to air resistance and 10\% when the ball comes in contact with the ground. Till what height will the ball bounce back again?

What is the coefficient of restitution of a dropped ball?

The coefficient of restitution for this collision is defined by: e= √ {h/H}, where H is the initial height the ball was dropped from and h is the height reached by it after it hits the floor for the first time, as the ball attains half the height after each collision, e= 1/√2. Before making the second impact the again falls through 1/2 metre.