At what rate should the earth rotate so that apparent G at the equator become zero?

or √9.8×10−56.4=√1.5×10−6=1.2×10−3rad/sT=2πω=2×3.141.2×10−3=6.281.2×10−3=1.41 hour.

At what rate should the earth rotates so that?

The earth rotates once every 23 hours, 56 minutes and 4.09053 seconds, called the sidereal period, and its circumference is roughly 40,075 kilometers. Thus, the surface of the earth at the equator moves at a speed of 460 meters per second–or roughly 1,000 miles per hour.

At what speed does the earth rotate when measured from the equator?

(This area is also called the equator.) If you estimate that a day is 24 hours long, you divide the circumference by the length of the day. This produces a speed at the equator of about 1,037 mph (1,670 km/h). You won’t be moving quite as fast at other latitudes, however.

How far at the equator does the earth rotate in 1 hour?

At the equator, its circumference is roughly 40,075 kilometres, so dividing this by the length of day means that, at the equator, Earth spins at about 1670 kilometres per hour.

What is the angular velocity at any point on the equator so that the body feels weightlessness?

Therefore the value of angular velocity of Earth for which object at equator becomes weightless is \[ 1.2\times {{10}^{-1}}\text{ rad }{{\text{s}}^{-1}}\] . So, the correct answer is “Option C”.

How fast does the Earth spin at the South Pole?

The South Pole is the other point where Earth’s axis of rotation intersects its surface, in Antarctica. Earth rotates once in about 24 hours with respect to the Sun, but once every 23 hours, 56 minutes and 4 seconds with respect to other distant stars (see below).

How much does the Earth rotate in an hour?

The Earth rotates approximately 15 degrees in one hour. This is determined by dividing the number of degrees in one full rotation (360) by the number of hours in one day.

How long would a day last if Earth were rotating so fast?

With a 1 mph speed increase, the day would only get about a minute and a half shorter and our internal body clocks, which stick to a pretty strict 24-hour schedule, probably wouldn’t notice. But if we were rotating 100 mph faster than usual, a day would be about 22 hours long.

How many hours would make a day of the Earth were rotating at such?

Therefore, one day on the Earth would be 1.4h if the Earth is rotating at such a high speed that the weight of a body on the equator was zero. Hence the correct answer is option B.

What should be the angular velocity of the earth so that the object at the equator is in a state of weightlessness G 10 and the radius of the Earth 6400 km?

The angular speed of earth is “rad s”^(-1), so that the object on equator may appear weightless, is (radius of earth = 6400 km) ∴ω=√gR=√9.86400×103=1.23×10-3rad s-1.