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What is the length of the pendulum whose time period is 2 second?

What is the length of the pendulum whose time period is 2 second?

Calculation : ⚽ Second pendulum is the simple pendum, having time period of 2 second. Its effective length is 99.992cm or approximate one metre on earth.

What is the formula for the length of a pendulum?

A mass m suspended by a wire of length L is a simple pendulum and undergoes simple harmonic motion for amplitudes less than about 15º. The period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity.

What is the length of a pendulum that has a period of 0.500 s G 9.80 M s2?

Then we get L is T squared times g divided by 4π squared. So that’s 0.500 seconds squared times 9.80 meters per second squared divided by 4π squared which is 0.06206 meters which is 6.21 centimeters.

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How do you find the length of a second pendulum?

For a point mass on a weightless string of length L swinging with an infinitesimally small amplitude, without resistance, the length of the string of a seconds pendulum is equal to L = g/π2 where g is the acceleration due to gravity, with units of length per second squared, and L is the length of the string in the same …

What is the length of a simple pendulum whose period is 1 second?

Answer: A simple pendulum with a period of 1 second will have a length of 0.25 meters or 25 centimeters.

How do you solve a pendulum equation?

How to analyze a pendulum in swing

  1. Determine the length of the pendulum.
  2. Decide a value for the acceleration of gravity.
  3. Calculate the period of oscillations according to the formula above: T = 2π√(L/g) = 2π * √(2/9.80665) = 2.837 s .
  4. Find the frequency as the reciprocal of the period: f = 1/T = 0.352 Hz .

How do you solve a pendulum?

What is second pendulum calculate the length of second pendulum at a place where G 9.8 m s2?

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The length of a second’s pendulum at a place where g = 9.8m/s ^2 is 90.2 cm.

What is the length of second pendulum if G 9.8m SEC?

The length of a second’s pendulum at a place where g = 9.8m/s 2 is 90.2 cm.

What is the length of simple pendulum?

about 100cm
The length of a simple pendulum is about 100cm , known to have an accuracy of 1mm . Its period of oscillation is 2s , determined by measuring the time for 100 oscillations using a clock of 0.1s resolution.

How do you find the length of a second’s pendulum?

Find the length of a second’s pendulum at a place where g = 10 m s -2 (Take π = 3.14) Let ‘l’ be the length of the seconds’ pendulum.

What is a simple pendulum?

Simple Pendulum is a mass (or bob) on the end of a massless string, which when initially displaced, will swing back and forth under the influence of gravity over its central (lowest) point. Use this online simple pendulum calculator to calculate period, length and acceleration of gravity alternatively with the other known values.

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What is the period of this pendulum correct to 3 significant figures?

T is the period in seconds; L is the length in meters and g is the acceleration due to gravity which is equal to 9.81 m/s^2 near the equator. The period of this pendulum correct to 3 significant figures is 2.00 seconds. Dwayne is in hot water for his latest comments.

What is BYJU’s simple pendulum calculator?

Simple Pendulum Calculator is a free online tool that displays the time period of a given simple pendulum. BYJU’S online simple pendulum calculator tool makes the calculation faster, and it shows the time period value in a fraction of seconds. How to Use the Simple Pendulum Calculator?