How many numbers are there between 99 and 1000 such that digit 8?

Detailed Solution. ∴ The required result will be 90.

How many numbers are there between 99 and 1000 such that the digit?

90 numbers
7 is in the unit’s place. The middle digit can be any one of the 10 digits from 0 to 9. The digit in hundred’s place can be any one of the 9 digits from 1 to 9. Therefore by the fundamental principle of counting there are 10 × 9 = 90 numbers between 99 and 1000 having 7 in the unit’s place.

How many times does the digit 8 occur while using number upto 99?

Answer: 19 8’s occur from 1 to 100. 8, 18, 28, 38, 48, 58, 68, 78, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89 and 98.

How many numbers are there between 100 and 1000 in which the sum of digits is equal to 3?

We know that numbers between 100 and 1000 will be 3 digit integers. Let the arrangement be ABC where A,B,C represent distinct digits. We have 9 options for A (as 0 can not start a 3 digit number), 9 options again for B and 8 for C, giving a total of 9*9*8 = 648 options. B is the correct answer.

How many numbers are there between 100 and 1000 which have exactly one of their digits as7?

Hence, the numbers between 100 and 1000 having the digit 7 exactly once are 72 + 72 + 81 = 225.

How many numbers are there between 100 and 1000 if 100 is included and 1000 is excluded How many of these have I either 2 or 9 as each digit?

So, we have to form 3-digit numbers by using 2 and 9. Clearly, the repetition of digit is allowed. Each one of the unit’s ten’s and hundred’s places can be filled in 2 ways. Hence, the required number of numbers =(2×2×2)=8.

How many 3 digit numbers between 99 and 1000 have 7?

Therefore, by the fundamental principle of counting, there are 10 × 9 = 90 numbers between 99 and 1000 having 7 in the unit’s place. (ii) Total number of 3 digit numbers having atleast one of their digits as 7 = (Total numbers of three digit numbers) – (Total number of 3 digit numbers in which 7 does not appear at all). = 900 – 648 = 252.

How many times does 8 come at the same place between 99-1000?

Numbers between 99 and 1000 are 100 to 999, i.e. all three digit numbers. Now, for 100 to 200: 8 will come at the unit’s place 10 times, i.e. 108, 118, 128…. 198. Similar will be the case with number sets of 201-300, 301-400 etc. Hence, the number of times that 8 will come at unit’s place between 99 and 1000 = 10 × 9 = 90

How many 10 9 numbers are there from 99 to 899?

From 99 to 799 there are 7 (10+9) numbers and 800 to 899 there are 100 numbers.and from 900 to 1000 there are 10+9 numbers. *there are 252 numbers. How many times does the digit 1 appear in the numbers from 10 to 99?

How many numbers arc there between 99 and 1000?

How many numbers arc there between 99 and 1000 such that the digit 8 occupies the units place? Please log in or register to add a comment. Numbers between 99 and 1000 are 100 to 999, i.e. all three digit numbers. Now, for 100 to 200: 8 will come at the unit’s place 10 times, i.e. 108, 118, 128…. 198. Please log in or register to add a comment.