How many numbers greater than 2000 can be formed with the digits?

The answer is 120 numbers (5!). all of which are greater than 2000.

How many ways can 4 digit numbers greater than 2000 be formed using the digits 0 1,2 3 4 If these numbers formed without repetition are even?

Hence they can filled in 4 ways each. Therefore the number of numbers that can be formed with the digits 1,2,3,4 which are more than 2000, with repetition allowed is 3 x 4 x 4 x 4 = 192.

How many no greater than 20000 can be formed?

Answer: The number of numbers greater than 20000 that can be formed using the digits 0 1 2 3 4 9, digits being repeated, is 5,183.

How many numbers greater than 4 000 can be formed?

Hence, the number of numbers that are greater than 4000 which can be formed using the digits 2, 3, 4, 5, 6 without repetition is 192. Note: You can also use the permutation formula nPr=n! (n−r)!

How many numbers between 100 and 1000 can be formed?

Hence the total number lying between 100 and 1000 which can be formed with digits 0, 1, 2, 3, 4, 5, 6, 7 are 294 numbers i.e. \[{}^{8}{{P}_{3}}-{}^{7}{{P}_{2}}\].

How many numbers greater than 1000000 can be formed?

Example 23 (Method 1) How many numbers greater than 1000000 can be formed by using the digits 1, 2, 0, 2, 4, 2, 4? There are total 7 digits in 1000000 We need to form a 7 digit number using the digits 1, 2, 0, 2]

How many two digit numbers can be greater than 2000?

Only a four digit number is greater than 2000. So we’ve to use all four digits. The first digit can’t be 1 as number required is greater than 2000. So there are three possibilities 2,3,4. For second digit it can be 1 or remaining two digits. Hence three ways.

How many numbers are greater than 2 in 23000?

So either the first digit is greater than 2 or the first digit is 2 and the second one is greater equal 3 because all digits given are greater than 0 the remaining 3 digits in 23,000. So we have 3 digits that are greater than 2 and the remaining 4 digits may be any order.

How many ways can a 5-digit number be written with 4 digits?

First digit is 3, 5 or 6. First digit is 2 and second digit is 3, 5 or 6. The number will be a 5 -digit number. Let’s give it 5 place holders: Case 1: The first digit has 3 choices. Excluding the first digit used, there are 4 choices for the remaining 4 digits. Hence, number of ways = 3 × 4 × 3 × 2 × 1 = 72