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What is the image of the point 1 3 4 in plane 2x YZ 3 0?

What is the image of the point 1 3 4 in plane 2x YZ 3 0?

The image of the point (1, 3, 4) with respect to the plane 2x – y + z + 3 = 0 is. A general point on this line is (2k + 1, -k + 3, k + 4). ∴ Coordinates of N are (-2 + 1, 1 + 4, -1 + 4, -1 + 4), i.e., N (-1, 4, 3). Let Q (α, β, γ) be the image of P in the given plane.

How do you find the mirror image of a point on a line?

We know that the image of the point about the line y=x can be obtained by interchanging the x-coordinate and y-coordinate of the point. For instance, the image of the point (a,b) about the line y=x is (b,a). So, the image of point A(1,2) is B(2,1).

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What is the formula for image of a point?

For finding the image of the point in the same line, we just multiply the rightmost term by 2. The image of the point is at the same distance from the line as the point itself is from the line. So, we have to multiply it by 2.

How do you find the line of reflection on a plane?

In a plane (or, respectively, 3-dimensional) geometry, to find the reflection of a point drop a perpendicular from the point to the line (plane) used for reflection, and extend it the same distance on the other side. To find the reflection of a figure, reflect each point in the figure.

How do you find the coordinates of an image on a plane?

Three Dimensional Geometry Find the coordinates of the image of the point (1, 3, 4) in the plane 2x – y +z + 3 = 0. Direction ratios of normal to the plane are 2,–1, 1. Let M be foot of perpendicular from P(l, 3, 4) to the plane. ∴ 4r + 2 + r – 3 + r + 4 + 3 = 0.

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What is the image of the point 4 5 by taking Y axis as a mirror?

Explanation: The mirror image of the point A(4,5) on the y-axis is A'(-4,5).

How do you find the mirror image of a point in class 9?

Mirror image with respect to x-axis: In this case, image of P (x,y) become P (x, -y). Thus, to find the image of any point along the x-axis, we keep the x-coordinate same and sign of y-coordinate gets changed. Any point on the mirror remains the same.