Is momentum decreases by 20\%?

The linear momentum of body is decreased by 20 \%.

When the KE of a body is increased by 300?

i.e. Momentum will increase by 100\%.

What can momentum be decreased by?

Momentum of a object is equal to its mass multiplied by its velocity. (Momentum is a vector quantity because velocity is a vector). Decreasing either mass or velocity will decrease momentum.

What will be the kinetic energy of an electron if its velocity is increased by 20\%?

On 20\% increase of p, KE varies as (1.2p)^2 or 1.44p^2. Hence, increase in KE is 44\%.

What happens to the Ke if its velocity is reduced by ¼TH of the initial velocity?

Now, the velocity is reduced to 1/3rd or the initial velocity. The final kinetic energy is given by. So, K.E. becomes 1/9th of its initial K.E.

What happens to kinetic energy when momentum is decreased by 20\%?

If the momentum of a body is decreased by 20\% its kinetic energy is decreased by 36\%. When KE is still unaltered it is KE = 1/2mv^2. The decreased in its KE is 36\%.

What happens when the linear momentum of a body is increased?

Similar questions If the linear momentum of a body is increased by 50 \%, the Kinetic energy will be increased by   Medium View solution A body of mass 1 kg is thrown up vertically from the ground such that it reaches a height of 40 m. Find its kinetic energy when it is half way up.

What are two ways to decrease momentum?

Decrease velocity and/or decrease mass. Momentum of a object is equal to its mass multiplied by its velocity. (Momentum is a vector quantity because velocity is a vector). Decreasing either mass or velocity will decrease momentum. Some or all of the momentum of an object can be transferred to another object by colliding with it.

What is the percent change in K E after 20\% increase?

Since the momentum p increases by 20\%, so the final momentum becomes 1.2p. So, \% change in K E = 44\%. Was this answer helpful?

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